256(t)=16t^2

Solution for 256(t)=16t^2 equation:

256(t)=16t^2

We move all terms to the left:

256(t)-(16t^2)=0

determiningTheFunctionDomain
-16t^2+256t=0

a = -16; b = 256; c = 0;
Δ = b2-4ac
Δ = 2562-4·(-16)·0
Δ = 65536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{65536}=256$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(256)-256}{2*-16}=\frac{-512}{-32}
=+16
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(256)+256}{2*-16}=\frac{0}{-32}
=0
$